VB.net String Functions

 Syntax String Functions with Description
Asc, AscW   -> Returns an Integer value representing the char code corresponding to a char.
Dim codeInt As Integer ' The following line of code sets codeInt to 65. codeInt = Asc("A") ' The following line of code sets codeInt to 97. codeInt = Asc("a") ' The following line of code sets codeInt to 65. codeInt = Asc("Apple")
 
Chr, ChrW   -> Returns the character associated with the specified character code.
Dim associatedChar As Char ' Returns "A". associatedChar = Chr(65) ' Returns "a". associatedChar = Chr(97) ' Returns ">". associatedChar = Chr(62) ' Returns "%". associatedChar = Chr(37)
 
Filter       -> Returns a zero-based array containing a subset of a String array 
Dim TestStrings(2) As String TestStrings(0) = "This" TestStrings(1) = "Is" TestStrings(2) = "It" Dim subStrings() As String ' Returns ["This", "Is"]. subStrings = Filter(TestStrings, "is", True, CompareMethod.Text) ' Returns ["This"]. subStrings = Filter(TestStrings, "is", True, CompareMethod.Binary) ' Returns ["Is", "It"]. subStrings = Filter(TestStrings, "is", False, CompareMethod.Binary)

Format ->  According to instructions contained in a format String expression.
Dim TestDateTime As Date = #1/27/2001 5:04:23 PM# Dim TestStr As String ' Returns current system time in the system-defined long time format. TestStr = Format(Now(), "Long Time") ' Returns current system date in the system-defined long date format. TestStr = Format(Now(), "Long Date") ' Also returns current system date in the system-defined long date ' format, using the single letter code for the format. TestStr = Format(Now(), "D") ' Returns the value of TestDateTime in user-defined date/time formats. ' Returns "5:4:23". TestStr = Format(TestDateTime, "h:m:s") ' Returns "05:04:23 PM". TestStr = Format(TestDateTime, "hh:mm:ss tt") ' Returns "Saturday, Jan 27 2001". TestStr = Format(TestDateTime, "dddd, MMM d yyyy") ' Returns "17:04:23". TestStr = Format(TestDateTime, "HH:mm:ss") ' Returns "23". TestStr = Format(23) ' User-defined numeric formats. ' Returns "5,459.40". TestStr = Format(5459.4, "##,##0.00") ' Returns "334.90". TestStr = Format(334.9, "###0.00") ' Returns "500.00%". TestStr = Format(5, "0.00%")
 
FormatCurrency  ->Returns an expression formatted as a currency value 
Dim TestDebt As Double = -4456.43 Dim TestString As String ' Returns "($4,456.43)". TestString = FormatCurrency(TestDebt, , , TriState.True, TriState.True)
 
FormatDateTime      -> Returns a string expression representing a date/time value.
Dim TestDate As DateTime = #3/12/1999# ' FormatDateTime returns "Friday, March 12, 1999". ' The time information is neutral (00:00:00) and therefore suppressed. Dim TestString As String = FormatDateTime(TestDate, DateFormat.LongDate)

FormatNumber-> Returns an expression formatted as a number.
Dim TestNumber As Integer = 45600 ' Returns "45,600.00". Dim TestString As String = FormatNumber(TestNumber, 2, , , TriState.True) 

FormatPercent->Returns an expression formatted as a percentage with a trailing % character.
Dim TestNumber As Single = 0.76 ' Returns "76.00%". Dim TestString As String = FormatPercent(TestNumber)

InStr->Returns an integer specifying the start position of the first occurrence of one string within another.
' String to search in. Dim SearchString As String = "XXpXXpXXPXXP" ' Search for "P". Dim SearchChar As String = "P" Dim TestPos As Integer ' A textual comparison starting at position 4. Returns 6. TestPos = InStr(4, SearchString, SearchChar, CompareMethod.Text) ' A binary comparison starting at position 1. Returns 9. TestPos = InStr(1, SearchString, SearchChar, CompareMethod.Binary) ' If Option Compare is not set, or set to Binary, return 9. ' If Option Compare is set to Text, returns 3. TestPos = InStr(SearchString, SearchChar) ' Returns 0. TestPos = InStr(1, SearchString, "W")   

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